The lengths of mercury thread in a mercury thermometer are
10 mm when the bulb is in melting ice;
130 mm when the bulb is in the steam above boiling water and 40 mm when the bulb is in a liquid A.
What is the temperature of liquid A?
Answer:
l0 = 10mm
l100 = 130mm
lθ = 40mm
\begin{gathered}
T = \frac{{l_\theta - l_0 }}
{{l_{100} - l_0 }} \times 100^o C \hfill \\
T = \frac{{40 - 10}}
{{130 - 10}} \times 100^o C \hfill \\
T = \frac{{30}}
{{120}} \times 100^o C \hfill \\
T = 25^o C \hfill \\
\end{gathered}