What will be the final temperature if 500 cm
3 of water at 0 °C is added to 200cm
3 of water at 90 °C? [Density of water = 1gcm
-3]
Answer:
The density of water is 1g/cm3, which means the mass of 1 cm3 of water is equal to 1g.
Let the final temperature = θ
m1 = 500g = 0.5kg
c1 = c
θ1 = θ - 0 = θ
m2 = 200g = 0.2kg
c2 = c
θ2 = 90 - θ
m1c1θ1 = m2c2θ2
(0.5) c ( θ ) = (0.2) c ( 90 - θ )
0.5 θ = 18 - 0.2 θ
0.5 θ + 0.2 θ = 18
0.7 θ = 18
θ = 25.71 oC