# Ticker Tape

Card 1: Ticker Timer

## Ticker Timer

• A ticker-timer consists of an electrical vibrator which vibrates 50 times per second.
• This enables it to make 50 dots per second on a ticker-tape being pulled through it.
• The time interval between two adjacent dots on the ticker-tape is called one tick.
• One tick is equal to  1/50 s or 0.02 s.
Card 2: Analysing Ticker Tape 1 - Uniform Velocity

## Uniform Velocity

• The distance of the dots is equally distributed.
• All lengths of tape in the chart are of equal length.
• The object is moving at a uniform velocity.
Card 3: Analysing Ticker Tape 1 - Uniform Acceleration

## Uniform Acceleration

• The distance between the dots increases uniformly.
• The length of the strips of tape in the chart increase uniformly.
• The velocity of the object is increasing uniformly, i.e. the object is moving at a constant acceleration.
Card 4: Analysing Ticker Tape 1 - Uniform Deceleration

## Uniform Deceleration

• The distance between the dots decreases uniformly.
• The length of the strips of tape in the chart decreases uniformly.
• The velocity of the object is decreasing uniformly, i.e. the object is decelerating uniformly.
Card 5: Finding velocity from ticker tape

## Finding Velocity

Velocity of a motion can be determined by using ticker tape through the following equation:

Caution!:
t is time taken from the first dot to the last dot of the distance measured.

Example 1

Diagram 2.4 shows a strip of ticker tape that was pulled through a ticker tape timer that vibrated at 50 times a second. What is the

1. time taken from the first dot to the last dot?
2. average velocity of the object that is represented by the ticker tape?

a.
There are 15 ticks from the first dot to the last dot, hence

Time taken = 15 × 0.02s = 0.3s

b.
Distance travelled = 15cm

            $\begin{gathered} v = \frac{s} {t} \hfill \\ v = \frac{{15cm}} {{0.3s}} = 50cms^{ - 1} \hfill \\ \end{gathered}$


Card 6: Findng acceleration

## Finding Acceleration

Acceleration of a motion can be determined by using ticker tape through the following equation:

Caution!:
t is time taken from the initial velocity to the final velocity.

Example 2

The ticker-tape in figure above was produced by a toy car moving down a tilted runway. If the ticker-tape timer produced 50 dots per second, find the acceleration of the toy car.

In order to find the acceleration, we need to determine the initial velocity, the final velocity and the time taken for the velocity change.

Initial velocity,

            u = \frac{s}
{t} = \frac{{3cm}}
{{0.02s}} = 150cms^{ - 1}

            v = \frac{s}
{t} = \frac{{0.5cm}}
{{0.02s}} = 25cms^{ - 1}


Time taken for the velocity change,
t = (0.5 + 4 + 0.5) ticks = 5 ticks
t = 5 × 0.02s = 0.1s

Acceleration,

            a = \frac{{v - u}}
{t} = \frac{{25 - 150}}
{{0.1}} =  - 1250cms^{ - 1}

Example 3

A trolley is pushed up a slope. Diagram above shows ticker tape chart that show the movement of the trolley. Every section of the tape contains 5 ticks. If the ticker-tape timer produced 50 dots per second, determine the acceleration of the trolley.

In order to find the acceleration, we need to determine the initial velocity, the final velocity and the time taken for the velocity change.

Initial velocity,

            u = \frac{s}
{t} = \frac{{5cm}}
{{5 × 0.02s}} = 50cms^{ - 1}

            v = \frac{s}
{t} = \frac{{1cm}}
{{5 × 0.02s}} = 10cms^{ - 1}


Time taken for the velocity change,
t = (2.5 + 5 + 5 + 5 + 2.5) ticks = 40 ticks
t = 40 × 0.02s = 0.8s

Acceleration,

            a = \frac{{v - u}}
{t} = \frac{{10 - 50}}
{{0.8}} =  - 50cms^{ - 1}

Card 7: Empty Card

Card 8: Empty Card

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