Ticker Tape

Card 1: Ticker Timer

Ticker Timer

  • A ticker-timer consists of an electrical vibrator which vibrates 50 times per second.
  • This enables it to make 50 dots per second on a ticker-tape being pulled through it.
  • The time interval between two adjacent dots on the ticker-tape is called one tick.
  • One tick is equal to  1/50 s or 0.02 s.
Card 2: Analysing Ticker Tape 1 - Uniform Velocity

Uniform Velocity

  • The distance of the dots is equally distributed.
  • All lengths of tape in the chart are of equal length.
  • The object is moving at a uniform velocity.
Card 3: Analysing Ticker Tape 1 - Uniform Acceleration

Uniform Acceleration

  • The distance between the dots increases uniformly.
  • The length of the strips of tape in the chart increase uniformly.
  • The velocity of the object is increasing uniformly, i.e. the object is moving at a constant acceleration.
Card 4: Analysing Ticker Tape 1 - Uniform Deceleration

Uniform Deceleration

  • The distance between the dots decreases uniformly.
  • The length of the strips of tape in the chart decreases uniformly.
  • The velocity of the object is decreasing uniformly, i.e. the object is decelerating uniformly.
Card 5: Finding velocity from ticker tape

Finding Velocity

Velocity of a motion can be determined by using ticker tape through the following equation:

Caution!:
t is time taken from the first dot to the last dot of the distance measured.

Example 1

Diagram 2.4 shows a strip of ticker tape that was pulled through a ticker tape timer that vibrated at 50 times a second. What is the

  1. time taken from the first dot to the last dot?
  2. average velocity of the object that is represented by the ticker tape?

Answer:

a.
There are 15 ticks from the first dot to the last dot, hence

Time taken = 15 × 0.02s = 0.3s

b.
Distance travelled = 15cm

            $\begin{gathered}
  v = \frac{s}
{t} \hfill \\
  v = \frac{{15cm}}
{{0.3s}} = 50cms^{ - 1}  \hfill \\ 
\end{gathered} $
            

Card 6: Findng acceleration

Finding Acceleration

Acceleration of a motion can be determined by using ticker tape through the following equation:

Caution!:
t is time taken from the initial velocity to the final velocity.

Example 2

The ticker-tape in figure above was produced by a toy car moving down a tilted runway. If the ticker-tape timer produced 50 dots per second, find the acceleration of the toy car.

Answer:

In order to find the acceleration, we need to determine the initial velocity, the final velocity and the time taken for the velocity change.

Initial velocity,

            u = \frac{s}
{t} = \frac{{3cm}}
{{0.02s}} = 150cms^{ - 1}
            
            v = \frac{s}
{t} = \frac{{0.5cm}}
{{0.02s}} = 25cms^{ - 1}
            

Time taken for the velocity change,
t = (0.5 + 4 + 0.5) ticks = 5 ticks
t = 5 × 0.02s = 0.1s

Acceleration,

            a = \frac{{v - u}}
              {t} = \frac{{25 - 150}}
              {{0.1}} =  - 1250cms^{ - 1}

Example 3

A trolley is pushed up a slope. Diagram above shows ticker tape chart that show the movement of the trolley. Every section of the tape contains 5 ticks. If the ticker-tape timer produced 50 dots per second, determine the acceleration of the trolley.

Answer:

In order to find the acceleration, we need to determine the initial velocity, the final velocity and the time taken for the velocity change.

Initial velocity,

            u = \frac{s}
{t} = \frac{{5cm}}
{{5 × 0.02s}} = 50cms^{ - 1}
            
            v = \frac{s}
{t} = \frac{{1cm}}
{{5 × 0.02s}} = 10cms^{ - 1}
            

Time taken for the velocity change,
t = (2.5 + 5 + 5 + 5 + 2.5) ticks = 40 ticks
t = 40 × 0.02s = 0.8s

Acceleration,

            a = \frac{{v - u}}
              {t} = \frac{{10 - 50}}
              {{0.8}} =  - 50cms^{ - 1}

Card 7: Empty Card

 

 

Card 8: Empty Card

 

 

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