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Series Circuit and Parallel Circuit
| a. |  |
b. |  |
Answer:
a. Effective resistance, R = 2 + 3 + 6 = 11Ω
b. Effective resistance, R = (1/5 + 1/5)-1 = 2.5 Ω
| a. |  |
b. |  |
Answer:
a. Effective resistance = 3 + (1/2 + 1/2)-1 = 4Ω
b.
{\text{Effective Resistance, }}R = (\frac{1}
{{2 + 7}} + \frac{1}
{{5 + 4}})^{ - 1} = 4.5\Omega
| a. |  |
b. |  |
Answer:
a. In a series circuit, the current at any points of the circuit is the same. Therefore, the reading of the ammeter is also 0.5A.
b. Reading of the ammeter, I = 6A - 2A = 4A
In the diagram above,
- find the reading of the ammeter.
- find the current flows through each of the resistors.
Answer:
a.
Resistance of the (whole) circuit = 2 + 4 = 6Ω
Potential difference across the whole circuit, V = 12V
Current, I = ?
V = IR
(12) = I(6)
I = 2A
Reading of the ammeter = 2A
b.
Since in a series circuit, the current at any points of the circuit is the same. Therefore, the current flows through each of the resistors is also 2A.
Find the reading of the given voltmeter(s) in the diagrams below
| a. |  |
b. |  |
Asnwer:
a. Reading of the voltmeter, V2 = 12 - 7 = 5V
b. The potential difference across all the resistor in a parallel circuit is the same. Therefore, the reading of the voltmeter V1 is also 5V
Find the potential difference across each of the resistors in the diagram above.
Answer:
The potential difference across the whole circuit = 12V, but the potential across the 2 resistor R1 and R2 are unknown. In order to find the potential difference across the resostors, we need to find current passing through the resistors.
V = 12V, R = 6Ω, I = ?
V = IR
(12) = I(6)
I = 2A
For resistor R1,
R = 2Ω, I = 2A, V = ?
V = IR
V = (2)(2) = 4V
For resistor R2,
R = 4Ω, I = 2A, V = ?
V = IR
V = (2)(4) = 8V
| a. |  |
c. |  |
| b. |  |
d. |  |
Answer:
a. Reading of the volmeter = e.m.f. = 3V
b. Reading of the volmeter = e.m.f. = 3V
c. Reading of the volmeter = e.m.f. = 3V
d. Reading of the volmeter = e.m.f. = 3V
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